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-16x^2+40x-25=0
a = -16; b = 40; c = -25;
Δ = b2-4ac
Δ = 402-4·(-16)·(-25)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{-40}{-32}=1+1/4$
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